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insensitive to temperature if the screw speed is at the low level but sensitive to temperature if the screw speed is at the high level. With the screw speed at a low level, the process should produce an average shrinkage of around 10% regardless of the temperature level chosen. Based on this initial analysis, the team decides to set both the mold temperature and the screw speed at the low level. This set of conditions should reduce the mean shrinkage of parts to around 10%. However, the variability in shrinkage from part to part is still a potential problem. In effect, the mean shrinkage can be adequately reduced by the above modi cations; however, the part-to-part variability in shrinkage over a production run could still cause problems in assembly. One way to address this issue is to see if any of the process factors affect the variability in parts shrinkage. Figure 14-35 presents the normal probability plot of the residuals. This plot appears satisfactory. The plots of residuals versus each factor were then constructed. One of these plots, that for residuals versus factor C (holding time), is shown in Fig. 14-36. The plot reveals much less scatter in the residuals at the low holding time than at the high holding time. These residuals were obtained in the usual way from a model for predicted shrinkage

y

From VQs, we have (Q5 = 0 ) 8 and (Q5 = l ) 2 5 Here, no restriction is implied on ( Q 5 ) O (although we do obtain a restriction on this bit in the analysis below) Now consider the constant bits of Q5, that is, those bits where Qk = Q5 From Table 516, we have (Qk = Q 5 ) 1 ..7,9..24,26..31 The function F5 selects between the bits of Q 4 and Q 3 , depending on the corresponding bits of Qj, with Q 3 selected if the bit of Q5 is 0, and Q 4 selected if the bit of Qs is 1 The analogous statement holds for Fi on the constant bits of Q 5 From Table 516, we see that the desired condition on VF:, is g riven by (VF5 = VQ4)9 .. 1618...

x 1 1

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A camera is nothing more than a tool for capturing light. In fact, it is a Latin word that means lightproof chamber. You simply send light into your lightproof chamber to make pictures. You control light by making adjustments to your camera, often referred to as setting the exposure, or make changes to the light by choosing the time of day to shoot, camera angle, background selection, ash use, and so on. As a visual artist, you use light and exposure to control the viewer s experience. Exposure is the amount of light that strikes your image sensor and is controlled by the exposure settings you have dialed in to your camera. Awareness of your subject s positioning or your camera s positioning will lead you to choose locations where you can easily control light by adding it or subtracting it. I often avoid an overly bright sky by moving my subject into soft shade and adjusting my exposure for the lower intensity of light or adding ash that lls in the new shadows caused by the shade. Once you decide on the scene and how to handle the light, the last step is to control the amount of light that will enter the camera, pass through the lens, aperture, and shutter, and nally strike your image sensor and make the image. You do this by setting the two most creative controls the camera possesses: aperture and shutter speed. A third method of controlling light, adjusting the ISO setting, controls how much light the image sensor needs to make a proper exposure. Correct ISO settings can determine how successful you are when shooting subjects like sports or action, close-ups, or landscapes by limiting or expanding the range of aperture and shutter speed settings available for that particular scene.

x 2 2

6.9375x1

21 and this will hold provided F selects Q&and F5 A selects Q 4 on these bits Since we have (Qk = Q5)9..16,18..21, (ie, these bits are among the constant bits of Q5) this will hold true provided that we have ( Q 5 = 1 ) 9..16,18..21 Also, (VF5 = V Q 3 ) 1 7 , 2 2 , 2 3 , 2 4 and this holds provided FA selects Q and F5 selects Q 3 Since these are also among the L constant bits of Q 5 , we require t,hat ( Q 5 = 0)17,22,23,24 For the remaining constant bits of Q we want (I$ = F5)j But each such 5 constant bit of Q5 is also a constant bits of Q 4 and Q3, that is, (Qi= Q 4 ) j and (QS = Q 3 ) j .

17.8125x2

where x1, x2, and x1x2 are coded variables that correspond to the factors A and B and the AB interaction. The residuals are then e y

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